number systems Model Questions & Answers, Practice Test for ibps po prelims
If the fractions $2/5, 3/4, 4/5, 5/7$ and $6/11$ are arranged in ascending order of their values, which one will be the fourth ?
Answer: (a)
Decimal equivalent of given fractions:
$2/5 = 0.4; 3/4 = 0.75; 4/5 = 0.8;$
$5/7 =0.714; 6/11 = 0.545$
Clearely, 0.4 < 0.545 < 0.714 < 0.75 < 0.8
∴ $2/5 < 6/11 < 5/7 < 3/4 < 4/5$
A number is successively divided by 5,6,8; leaving remainders 3, 4, 7 respectively. What will be the remainders if the order of divisors be reversed ?
Answer: (d)
Complete remainder = $d_1 d_2 r_ 3 + d_1 r_2 + r_1$
= 5 × 6 × 7 + 5 ×4 + 3 = 233.
Dividing 233, by reversing the divisors
i.e. by 8, 6, 5; respective remainders are 1, 5, 4.
What would be the sum of 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + ....... up to 15th term?
Answer: (a)
The sum forms A.P.
First term (a) = 1
Common difference (d)= 2
Sum of 15 term = $n/2(2a + (n - 1)d)$
Sum = $15/2(2 × 1 + (15 - 1)2) = 15/2 × 30 225$
Find the HCF of $(3^125 – 1)$ and $(3^35 – 1)$.
Answer: (c)
The solution of this question is based on the rule that:
The HCF of $(a^m – 1)$ and $(a^n – 1)$ is given by $(a^\text"HCF of m, n" –1)$
Thus, in this question the answer is : $(3^5 – 1)$.
Since 5 is the HCF of 35 and 125.
Unit place digit in the product of first 40 odd natural number is
Answer: (a)
Product of first 40 odd natural number
= 1 . 3 . 5 .7 . 9 . ............ 79.
= 15 .(7 .9 ............. 79)
= 15 × an odd number
So there will be 5 at unit place.
So answer is 5.
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